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CritPt / Challenge_47_main / Let (m)→(x,t) be a classical spin field defined for xinmathbb R and…
Problem
Answer published by the source. Consult the official source to check your work against its answer.
code template
Code
def answer():
r"""
Return the value of $\mathrm{Tr}(L^4)$ under the given spin configuration.
Inputs
----------
None
Outputs
----------
Tr_L4: float, value of $\mathrm{Tr}(L^4)$ for the spin configuration
$$\vec{m}(x) = ( \sin \theta \cos \phi,\, \sin \theta \sin \phi,\, \cos \theta )$$
"""
# ------------------ FILL IN YOUR RESULTS BELOW ------------------
Tr_L4 = ...
# ---------------------------------------------------------------
return Tr_L4problem description
# Problem setup:
Let be a classical spin field defined for
$x\in\mathbb R$ and . The field satisfies the unit-length constraint
\begin{equation}
\vec m\cdot\vec m=1.
\end{equation}
Let () denote the Pauli matrices, and define the matrix-valued field
\begin{equation}
m=\vec m\cdot\vec\sigma= \sum_{\alpha = 1}^3 m^\alpha\sigma_\alpha.
\end{equation}
The Lax operator is given by
\begin{equation}
L=[\mathcal H,m].
\end{equation}
Its action should be understood analogously to that of a quantum operator. Specifically, when acting on any matrix field , we have
\begin{equation}
L(n)=\mathcal H(mn)-m\,\mathcal H(n),
\end{equation}
where $\mathcal H$ is the Hilbert transform. For a scalar function , the Hilbert transform is defined as
\begin{equation}
\mathcal H[f(x)]=\frac{\mathrm P}{\pi}\int_{-\infty}^{\infty}\frac{f(y)}{x-y}\,dy=\frac1{\pi x}\!*f(x).
\end{equation}
We may write either $\mathcal H(f)$ or $f_{\mathcal H}$ for this quantity. When $\mathcal H$ acts on a matrix field, it is understood component-wise. We assume the boundary condition
\begin{equation}
\vec m(x\to\pm\infty)=\text{constant},
\end{equation}
i.e., the spin field converges to a fixed vector as .
The trace includes both the matrix indices and the spatial integral:
\begin{equation}
\mathrm{Tr}(\cdot)=\int_{-\infty}^{\infty}dx\,\mathrm{tr}(\cdot).
\end{equation}
# Main problem:
Compute
\begin{equation}
\mathrm{Tr}(L^4),
\end{equation}
for the following spin configuration:
\begin{equation}
\vec{m}(x) = ( \sin \theta \cos \phi,\, \sin \theta \sin \phi,\, \cos \theta ),
\end{equation}
which is a wave packet parameterized by
\begin{equation}
\theta(x) = x, \qquad \phi(x) = \frac{2\pi}{3}e^{-x^2}.
\end{equation}
Evaluate this quantity to at least six decimal places.Plain-text mathematical notation (without MathML)
# Problem setup:
Let (m)→(x,t) be a classical spin field defined for $x\in\mathbb R$ and t∈[0,∞). The field satisfies the unit-length constraint
\begin{equation}
\vec m\cdot\vec m=1.
\end{equation}
Let σ_(α) (α=1,2,3) denote the Pauli matrices, and define the 2×2 matrix-valued field
\begin{equation}
m=\vec m\cdot\vec\sigma= \sum_{\alpha = 1}^3 m^\alpha\sigma_\alpha.
\end{equation}
The Lax operator is given by
\begin{equation}
L=[\mathcal H,m].
\end{equation}
Its action should be understood analogously to that of a quantum operator. Specifically, when acting on any 2×2 matrix field n(x), we have
\begin{equation}
L(n)=\mathcal H(mn)-m\,\mathcal H(n),
\end{equation}
where $\mathcal H$ is the Hilbert transform. For a scalar function f(x), the Hilbert transform is defined as
\begin{equation}
\mathcal H[f(x)]=\frac{\mathrm P}{\pi}\int_{-\infty}^{\infty}\frac{f(y)}{x-y}\,dy=\frac1{\pi x}\!*f(x).
\end{equation}
We may write either $\mathcal H(f)$ or $f_{\mathcal H}$ for this quantity. When $\mathcal H$ acts on a matrix field, it is understood component-wise. We assume the boundary condition
\begin{equation}
\vec m(x\to\pm\infty)=\text{constant},
\end{equation}
i.e., the spin field converges to a fixed vector as x→±∞.
The trace Tr(⋅) includes both the 2×2 matrix indices and the spatial integral:
\begin{equation}
\mathrm{Tr}(\cdot)=\int_{-\infty}^{\infty}dx\,\mathrm{tr}(\cdot).
\end{equation}
# Main problem:
Compute
\begin{equation}
\mathrm{Tr}(L^4),
\end{equation}
for the following spin configuration:
\begin{equation}
\vec{m}(x) = ( \sin \theta \cos \phi,\, \sin \theta \sin \phi,\, \cos \theta ),
\end{equation}
which is a wave packet parameterized by
\begin{equation}
\theta(x) = x, \qquad \phi(x) = \frac{2\pi}{3}e^{-x^2}.
\end{equation}
Evaluate this quantity to at least six decimal places.Original LaTeX notation
# Problem setup:
Let $\vec m(x,t)$ be a classical spin field defined for $x\in\mathbb R$ and $t\in[0,\infty)$. The field satisfies the unit-length constraint
\begin{equation}
\vec m\cdot\vec m=1.
\end{equation}
Let $\sigma_\alpha$ ($\alpha=1,2,3$) denote the Pauli matrices, and define the $2\times2$ matrix-valued field
\begin{equation}
m=\vec m\cdot\vec\sigma= \sum_{\alpha = 1}^3 m^\alpha\sigma_\alpha.
\end{equation}
The Lax operator is given by
\begin{equation}
L=[\mathcal H,m].
\end{equation}
Its action should be understood analogously to that of a quantum operator. Specifically, when acting on any $2\times2$ matrix field $n(x)$, we have
\begin{equation}
L(n)=\mathcal H(mn)-m\,\mathcal H(n),
\end{equation}
where $\mathcal H$ is the Hilbert transform. For a scalar function $f(x)$, the Hilbert transform is defined as
\begin{equation}
\mathcal H[f(x)]=\frac{\mathrm P}{\pi}\int_{-\infty}^{\infty}\frac{f(y)}{x-y}\,dy=\frac1{\pi x}\!*f(x).
\end{equation}
We may write either $\mathcal H(f)$ or $f_{\mathcal H}$ for this quantity. When $\mathcal H$ acts on a matrix field, it is understood component-wise. We assume the boundary condition
\begin{equation}
\vec m(x\to\pm\infty)=\text{constant},
\end{equation}
i.e., the spin field converges to a fixed vector as $x\to\pm\infty$.
The trace $\mathrm{Tr}(\cdot)$ includes both the $2\times2$ matrix indices and the spatial integral:
\begin{equation}
\mathrm{Tr}(\cdot)=\int_{-\infty}^{\infty}dx\,\mathrm{tr}(\cdot).
\end{equation}
# Main problem:
Compute
\begin{equation}
\mathrm{Tr}(L^4),
\end{equation}
for the following spin configuration:
\begin{equation}
\vec{m}(x) = ( \sin \theta \cos \phi,\, \sin \theta \sin \phi,\, \cos \theta ),
\end{equation}
which is a wave packet parameterized by
\begin{equation}
\theta(x) = x, \qquad \phi(x) = \frac{2\pi}{3}e^{-x^2}.
\end{equation}
Evaluate this quantity to at least six decimal places.Discussion
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