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Omni-MATH / Let Z/nZ denote the set of integers considered modulo n (hence Z/nZ has n elements). Find all positive integers n for which there exists a bijective function g:Z/nZ→Z/nZ, such that…

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Let Z/nZ\mathbb{Z}/n\mathbb{Z} denote the set of integers considered modulo nn (hence Z/nZ\mathbb{Z}/n\mathbb{Z} has nn elements). Find all positive integers nn for which there exists a bijective function g:Z/nZZ/nZg: \mathbb{Z}/n\mathbb{Z} \to \mathbb{Z}/n\mathbb{Z}, such that the 101 functions g(x),g(x)+x,g(x)+2x,,g(x)+100xg(x), \quad g(x) + x, \quad g(x) + 2x, \quad \dots, \quad g(x) + 100x are all bijections on Z/nZ\mathbb{Z}/n\mathbb{Z}. [i]Ashwin Sah and Yang Liu[/i]
Plain-text mathematical notation (without MathML)
Let Z/nZ denote the set of integers considered modulo n (hence Z/nZ has n elements). Find all positive integers n for which there exists a bijective function g:Z/nZ→Z/nZ, such that the 101 functions
g(x), g(x)+x, g(x)+2x, …, g(x)+100x
are all bijections on Z/nZ.

[i]Ashwin Sah and Yang Liu[/i]
Original LaTeX notation
Let $\mathbb{Z}/n\mathbb{Z}$ denote the set of integers considered modulo $n$ (hence $\mathbb{Z}/n\mathbb{Z}$ has $n$ elements). Find all positive integers $n$ for which there exists a bijective function $g: \mathbb{Z}/n\mathbb{Z} \to \mathbb{Z}/n\mathbb{Z}$, such that the 101 functions
\[g(x), \quad g(x) + x, \quad g(x) + 2x, \quad \dots, \quad g(x) + 100x\]
are all bijections on $\mathbb{Z}/n\mathbb{Z}$.

[i]Ashwin Sah and Yang Liu[/i]

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