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BIG-Bench Extra Hard (BBEH) / Consider the following new operations:

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Consider the following new operations: $a # b$ equals $(2 - b) * a$ if a>ba > b and bb otherwise. a[]ba [] b equals (a−b)(a - b) if a−b>0a - b > 0; otherwise, it equals a+ba + b. $a & b$ equals $(a # b)$ if a−b>0a - b > 0; otherwise, it equals $-a # -b$. a][ba ][ b equals a−ba - b if gcd(a,b)==1gcd(a, b) == 1 and gcd(a,b)gcd(a, b) otherwise, where gcd stands for greatest common divisor. For brevity, we use a<op1><op2>ba <op1><op2> b to denote (aop1b)op2b(a op1 b) op2 b. For example, $4 +* -5$ means $(4 + -5) * -5$ and $4 *-- -5$ means $(4 * -5) -- -5$. Let A = ((((((((((((((((((((-8 +- ten) -#- six) -* 9) ][ one) ][-- one) -][ five) + 8) ][ 3) -+ -3) -- six) -][ -7) ][*& -5) [] -7) []+ -1) --& -5) # -6) &*- 3) ][+ 5) + -10) -## -9) Let B = (((((((((((((((((-10 + -3) + -2) - 4) # -4) *][ six) + -8) ][# -7) ++- -2) []&* -7) &## 8) ][ 4) ][ -4) ][ ten) *++ 4) &* 3) [] seven) +*[] ten) Let C = ((((eight #&- -2) &-][ (seven &-+ 8)) -+ ((-9 []# -3) []+ (3 &-- 10))) []][# (((-9 #- -10) #& (3 + -10)) -* ((4 -*+ -7) # (10 & 2)))). Compute A + B - C. Your final answer must be in number form.
Plain-text mathematical notation (without MathML)
Consider the following new operations:

$a # b$ equals $(2 - b) * a$ if a>b and b otherwise.
a[]b equals (a−b) if a−b>0; otherwise,  it equals a+b.
$a & b$ equals $(a # b)$ if a−b>0; otherwise,  it equals $-a # -b$.
a][b equals a−b if gcd(a,b)==1 and gcd(a,b) otherwise, where gcd stands for greatest common divisor.
For brevity, we use a<op1><op2>b to denote (aop1b)op2b. For example, $4 +* -5$ means $(4 + -5) * -5$ and $4 *-- -5$ means $(4 * -5) -- -5$.
Let A = ((((((((((((((((((((-8 +- ten) -#- six) -* 9) ][ one) ][-- one) -][ five) + 8) ][ 3) -+ -3) -- six) -][ -7) ][*& -5) [] -7) []+ -1) --& -5) # -6) &*- 3) ][+ 5) + -10) -## -9)
Let B = (((((((((((((((((-10 + -3) + -2) - 4) # -4) *][ six) + -8) ][# -7) ++- -2) []&* -7) &## 8) ][ 4) ][ -4) ][ ten) *++ 4) &* 3) [] seven) +*[] ten)
Let C = ((((eight #&- -2) &-][ (seven &-+ 8)) -+ ((-9 []# -3) []+ (3 &-- 10))) []][# (((-9 #- -10) #& (3 + -10)) -* ((4 -*+ -7) # (10 & 2)))).
Compute A + B - C. Your final answer must be in number form.
Original LaTeX notation
Consider the following new operations:

$a # b$ equals $(2 - b) * a$ if $a > b$ and $b$ otherwise.
$a [] b$ equals $(a - b)$ if $a - b > 0$; otherwise,  it equals $a + b$.
$a & b$ equals $(a # b)$ if $a - b > 0$; otherwise,  it equals $-a # -b$.
$a ][ b$ equals $a - b$ if $gcd(a, b) == 1$ and $gcd(a, b)$ otherwise, where gcd stands for greatest common divisor.
For brevity, we use $a <op1><op2> b$ to denote $(a op1 b) op2 b$. For example, $4 +* -5$ means $(4 + -5) * -5$ and $4 *-- -5$ means $(4 * -5) -- -5$.
Let A = ((((((((((((((((((((-8 +- ten) -#- six) -* 9) ][ one) ][-- one) -][ five) + 8) ][ 3) -+ -3) -- six) -][ -7) ][*& -5) [] -7) []+ -1) --& -5) # -6) &*- 3) ][+ 5) + -10) -## -9)
Let B = (((((((((((((((((-10 + -3) + -2) - 4) # -4) *][ six) + -8) ][# -7) ++- -2) []&* -7) &## 8) ][ 4) ][ -4) ][ ten) *++ 4) &* 3) [] seven) +*[] ten)
Let C = ((((eight #&- -2) &-][ (seven &-+ 8)) -+ ((-9 []# -3) []+ (3 &-- 10))) []][# (((-9 #- -10) #& (3 + -10)) -* ((4 -*+ -7) # (10 & 2)))).
Compute A + B - C. Your final answer must be in number form.

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Source and history

task_id
006b5b24-237d-5994-8217-2d55c54e6cce
task_key
bbeh~5fmultistep~5farithmetic--full--006b5b24-237d-5994-8217-2d55c54e6cce
task_revision_id
1
config / split
bbeh_multistep_arithmetic / full

Official source

initial import