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BIG-Bench Extra Hard (BBEH) / Consider the following new operations:

Problem

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input

Consider the following new operations: a!ba ! b equals (a+b)(a + b) if $a * b > 0$; otherwise, it equals a−ba - b. $a @ b$ equals min(a,b)min(a, b) if either aa or bb is prime and max(a,b)max(a, b) otherwise. a<>ba <> b equals (a!a)+b(a ! a) + b if b<2b < 2 and (b!b)+a(b ! b) + a otherwise. $a ~ b$ equals (a−b)(a - b) if a−b>0a - b > 0; otherwise, it equals a+ba + b. a;ba ; b equals $(2 - b) * a$ if a>ba > b and bb otherwise. a:ba : b equals $(b * a) - b$ if |a−b|<2|a-b| < 2 and $(a * b) - a$ otherwise. Let A = ((((5 @ 2) ; (5 ~ -5)) : ((ten <> -5) + (-1 ! -2))) : (((-7 * -4) ! (five ~ -9)) - ((six * 1) ~ (-6 ~ -8)))) Let B = (((((((((((((((((((one ; six) * -7) ~ -5) <> -8) @ two) ! -8) - -8) ; -3) @ -6) ~ -10) : -1) <> -8) - -5) * -4) - -4) : -9) + -5) ! 4) : -9) Let C = ((((((((((((((((((((((-2 @ three) : -5) * -3) + three) + -9) + 2) ; -3) ; one) ~ -4) ~ 6) ~ -10) ; 7) ! -3) <> one) - -2) ; four) <> -1) <> 3) - 5) @ -6) : -6) : -10). Compute A + B - C. Your final answer must be in number form.
Plain-text mathematical notation (without MathML)
Consider the following new operations:

a!b equals (a+b) if $a * b > 0$; otherwise,  it equals a−b.
$a @ b$ equals min(a,b) if either a or b is prime and max(a,b) otherwise.
a<>b equals (a!a)+b if b<2 and (b!b)+a otherwise.
$a ~ b$ equals (a−b) if a−b>0; otherwise,  it equals a+b.
a;b equals $(2 - b) * a$ if a>b and b otherwise.
a:b equals $(b * a) - b$ if |a−b|<2 and $(a * b) - a$ otherwise.

Let A = ((((5 @ 2) ; (5 ~ -5)) : ((ten <> -5) + (-1 ! -2))) : (((-7 * -4) ! (five ~ -9)) - ((six * 1) ~ (-6 ~ -8))))
Let B = (((((((((((((((((((one ; six) * -7) ~ -5) <> -8) @ two) ! -8) - -8) ; -3) @ -6) ~ -10) : -1) <> -8) - -5) * -4) - -4) : -9) + -5) ! 4) : -9)
Let C = ((((((((((((((((((((((-2 @ three) : -5) * -3) + three) + -9) + 2) ; -3) ; one) ~ -4) ~ 6) ~ -10) ; 7) ! -3) <> one) - -2) ; four) <> -1) <> 3) - 5) @ -6) : -6) : -10).
Compute A + B - C. Your final answer must be in number form.
Original LaTeX notation
Consider the following new operations:

$a ! b$ equals $(a + b)$ if $a * b > 0$; otherwise,  it equals $a - b$.
$a @ b$ equals $min(a, b)$ if either $a$ or $b$ is prime and $max(a, b)$ otherwise.
$a <> b$ equals $(a ! a) + b$ if $b < 2$ and $(b ! b) + a$ otherwise.
$a ~ b$ equals $(a - b)$ if $a - b > 0$; otherwise,  it equals $a + b$.
$a ; b$ equals $(2 - b) * a$ if $a > b$ and $b$ otherwise.
$a : b$ equals $(b * a) - b$ if $|a-b| < 2$ and $(a * b) - a$ otherwise.

Let A = ((((5 @ 2) ; (5 ~ -5)) : ((ten <> -5) + (-1 ! -2))) : (((-7 * -4) ! (five ~ -9)) - ((six * 1) ~ (-6 ~ -8))))
Let B = (((((((((((((((((((one ; six) * -7) ~ -5) <> -8) @ two) ! -8) - -8) ; -3) @ -6) ~ -10) : -1) <> -8) - -5) * -4) - -4) : -9) + -5) ! 4) : -9)
Let C = ((((((((((((((((((((((-2 @ three) : -5) * -3) + three) + -9) + 2) ; -3) ; one) ~ -4) ~ 6) ~ -10) ; 7) ! -3) <> one) - -2) ; four) <> -1) <> 3) - 5) @ -6) : -6) : -10).
Compute A + B - C. Your final answer must be in number form.

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Source and history

task_id
9b3226cc-3bc5-57ca-85b2-400d73caa672
task_key
bbeh~5fmultistep~5farithmetic--full--9b3226cc-3bc5-57ca-85b2-400d73caa672
task_revision_id
1
config / split
bbeh_multistep_arithmetic / full

Official source

initial import