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BIG-Bench Extra Hard (BBEH) / Consider the following new operations:

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Consider the following new operations: a!ba ! b equals $(a * b)$ if a−b>0a - b > 0; otherwise, it equals a+ba + b. a][ba ][ b equals (a−b)(a - b) if a−b>0a - b > 0; otherwise, it equals a+ba + b. $a ~ b$ equals min(a,b)min(a, b) if either aa or bb is prime and max(a,b)max(a, b) otherwise. a[]ba [] b equals (a][b)(a ][ b) if $a * b > 0$; otherwise, it equals −a][−b-a ][ -b. Let A = ((((three ! four) + (three * 7)) + ((-10 ! 10) + (-2 ][ -8))) ! (((-7 [] one) ! (-1 ~ -2)) + ((-9 ][ -2) ][ (-5 + 3)))) Let B = ((((one * -7) - (six ~ nine)) ~ ((-2 * seven) * (-7 ! seven))) * (((-8 * -5) [] (3 ][ -8)) [] ((-6 [] -10) - (7 ][ 6)))) Let C = (((((((((((((((((8 + -1) * -5) + 9) ][ -4) - -4) ! one) * six) ~ eight) + ten) ][ two) ][ 10) * six) ~ -6) ~ 4) ! five) ][ 10) ! -8). Compute A + B - C. Your final answer must be in number form.
Plain-text mathematical notation (without MathML)
Consider the following new operations:

a!b equals $(a * b)$ if a−b>0; otherwise,  it equals a+b.
a][b equals (a−b) if a−b>0; otherwise,  it equals a+b.
$a ~ b$ equals min(a,b) if either a or b is prime and max(a,b) otherwise.
a[]b equals (a][b) if $a * b > 0$; otherwise,  it equals −a][−b.

Let A = ((((three ! four) + (three * 7)) + ((-10 ! 10) + (-2 ][ -8))) ! (((-7 [] one) ! (-1 ~ -2)) + ((-9 ][ -2) ][ (-5 + 3))))
Let B = ((((one * -7) - (six ~ nine)) ~ ((-2 * seven) * (-7 ! seven))) * (((-8 * -5) [] (3 ][ -8)) [] ((-6 [] -10) - (7 ][ 6))))
Let C = (((((((((((((((((8 + -1) * -5) + 9) ][ -4) - -4) ! one) * six) ~ eight) + ten) ][ two) ][ 10) * six) ~ -6) ~ 4) ! five) ][ 10) ! -8).
Compute A + B - C. Your final answer must be in number form.
Original LaTeX notation
Consider the following new operations:

$a ! b$ equals $(a * b)$ if $a - b > 0$; otherwise,  it equals $a + b$.
$a ][ b$ equals $(a - b)$ if $a - b > 0$; otherwise,  it equals $a + b$.
$a ~ b$ equals $min(a, b)$ if either $a$ or $b$ is prime and $max(a, b)$ otherwise.
$a [] b$ equals $(a ][ b)$ if $a * b > 0$; otherwise,  it equals $-a ][ -b$.

Let A = ((((three ! four) + (three * 7)) + ((-10 ! 10) + (-2 ][ -8))) ! (((-7 [] one) ! (-1 ~ -2)) + ((-9 ][ -2) ][ (-5 + 3))))
Let B = ((((one * -7) - (six ~ nine)) ~ ((-2 * seven) * (-7 ! seven))) * (((-8 * -5) [] (3 ][ -8)) [] ((-6 [] -10) - (7 ][ 6))))
Let C = (((((((((((((((((8 + -1) * -5) + 9) ][ -4) - -4) ! one) * six) ~ eight) + ten) ][ two) ][ 10) * six) ~ -6) ~ 4) ! five) ][ 10) ! -8).
Compute A + B - C. Your final answer must be in number form.

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Source and history

task_id
9c651338-6442-531a-ac27-cb08a23af68a
task_key
bbeh~5fmultistep~5farithmetic--full--9c651338-6442-531a-ac27-cb08a23af68a
task_revision_id
1
config / split
bbeh_multistep_arithmetic / full

Official source

initial import