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BigCodeBench / BigCodeBench v0.1.0_hf 01d53e9b-f97f-5a49-9536-97b35f0ca002

Problem

Answer published by the source. Consult the official source to check your work against its answer.

complete prompt

from collections import Counter
import itertools
import random


# Constants
ALPHABET = 'abcdefghijklmnopqrstuvwxyz'

def task_func(list_of_lists, seed=0):
    """
    Count the frequency of each letter in a list of lists. If a list is empty, 
    fill it with a random sample from the alphabet, and then count the letters.
    
    Parameters:
    list_of_lists (list): The list of lists.
    seed (int): The seed for the random number generator. Defaults to 0.
    
    Returns:
    Counter: A Counter object with the frequency of each letter.
    
    Requirements:
    - collections.Counter
    - itertools
    - random.sample
    
    Example:
    >>> dict(task_func([['a', 'b', 'c'], [], ['d', 'e', 'f']]))
    {'a': 1, 'b': 2, 'c': 1, 'd': 1, 'e': 1, 'f': 1, 'm': 1, 'y': 1, 'n': 1, 'i': 1, 'q': 1, 'p': 1, 'z': 1, 'j': 1, 't': 1}
    """

instruct prompt

Count the frequency of each letter in a list of lists. If a list is empty, fill it with a random sample from the alphabet, and then count the letters.
The function should output with:
    Counter: A Counter object with the frequency of each letter.
You should write self-contained code starting with:

Code

from collections import Counter
import itertools
import random
# Constants
ALPHABET = 'abcdefghijklmnopqrstuvwxyz'
def task_func(list_of_lists, seed=0):

code prompt

Code

from collections import Counter
import itertools
import random
# Constants
ALPHABET = 'abcdefghijklmnopqrstuvwxyz'
def task_func(list_of_lists, seed=0):

entry point

task_func

libs

  • collections
  • random
  • itertools

Discussion

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Source and history

task_id
01d53e9b-f97f-5a49-9536-97b35f0ca002
task_key
default--v0~2e1~2e0~5fhf--01d53e9b-f97f-5a49-9536-97b35f0ca002
task_revision_id
1
config / split
default / v0.1.0_hf

Official source

initial import