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BigCodeBench / BigCodeBench v0.1.0_hf 28e2174f-b517-5f36-868b-35ea5d06c07b

Problem

Answer published by the source. Consult the official source to check your work against its answer.

complete prompt

from collections import Counter
import itertools

def task_func(d):
    """
    Count the occurrence of each integer in the values of the input dictionary, where each value is a list of integers,
    and return a dictionary with these counts. The resulting dictionary's keys are the integers, and the values are 
    their respective counts across all lists in the input dictionary.

    Parameters:
    d (dict): A dictionary where each key is a string and the value is a list of integers.

    Returns:
    dict: A dictionary where each key is an integer from any of the input lists, and the value is the count of 
            how often that integer appears in all the lists combined.

    Requirements:
    - collections.Counter
    - itertools
    
    Example:
    >>> d = {'a': [1, 2, 3, 1], 'b': [3, 4, 5], 'c': [1, 2]}
    >>> count_dict = task_func(d)
    >>> print(count_dict)
    {1: 3, 2: 2, 3: 2, 4: 1, 5: 1}
    """

instruct prompt

Count the occurrence of each integer in the values of the input dictionary, where each value is a list of integers, and return a dictionary with these counts. The resulting dictionary's keys are the integers, and the values are their respective counts across all lists in the input dictionary.
The function should output with:
    dict: A dictionary where each key is an integer from any of the input lists, and the value is the count of
    how often that integer appears in all the lists combined.
You should write self-contained code starting with:

Code

from collections import Counter
import itertools
def task_func(d):

code prompt

Code

from collections import Counter
import itertools
def task_func(d):

entry point

task_func

libs

  • collections
  • itertools

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Source and history

Official source

initial import