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BigCodeBench / BigCodeBench v0.1.0_hf 31fba451-22bb-5308-b5e8-6df402c6de09

Problem

Answer published by the source. Consult the official source to check your work against its answer.

complete prompt

import urllib.request
import zipfile
import os
import urllib.error


def task_func(
    url: str,
    save_path: str = "downloaded_file.zip",
    extract_path: str = "extracted_files",
) -> str:
    """
    Downloads, extracts, and deletes a ZIP file from a specified URL.

    The function includes comprehensive error handling to manage issues such as invalid URLs, unreachable servers, corrupted ZIP files, and file I/O errors. In the event of a failure, it provides a descriptive error message.

    Parameters:
    - url (str): The URL of the ZIP file to be downloaded.
    - save_path (str, optional): The local file path where the ZIP file will be saved temporarily. Defaults to 'downloaded_file.zip'.
    - extract_path (str, optional): The directory where the ZIP file's contents will be extracted. Defaults to 'extracted_files'.

    Returns:
    - str: The path to the directory where the ZIP file's contents have been extracted. Returns an error message in case of failure.

    Raises:
    - urllib.error.URLError: If the URL is invalid or the server cannot be reached. 
    In this case, the function returns a string in the format "URL Error: [error reason]".

    Requirements:
    - urllib
    - zipfile
    - os
    - urllib

    Example:
    >>> extracted_path = task_func('http://www.example.com/data.zip')
    >>> print(extracted_path)
    'extracted_files'


    """

instruct prompt

Downloads, extracts, and deletes a ZIP file from a specified URL. The function includes comprehensive error handling to manage issues such as invalid URLs, unreachable servers, corrupted ZIP files, and file I/O errors. In the event of a failure, it provides a descriptive error message.
The function should raise the exception for: urllib.error.URLError: If the URL is invalid or the server cannot be reached. In this case, the function returns a string in the format "URL Error: [error reason]".
The function should output with:
    str: The path to the directory where the ZIP file's contents have been extracted. Returns an error message in case of failure.
You should write self-contained code starting with:

Code

import urllib.request
import zipfile
import os
import urllib.error
def task_func(
    url: str,
    save_path: str = "downloaded_file.zip",
    extract_path: str = "extracted_files",
) -> str:

code prompt

Code

import urllib.request
import zipfile
import os
import urllib.error
def task_func(
    url: str,
    save_path: str = "downloaded_file.zip",
    extract_path: str = "extracted_files",
) -> str:

entry point

task_func

libs

  • urllib
  • zipfile
  • os

Discussion

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Source and history

task_id
31fba451-22bb-5308-b5e8-6df402c6de09
task_key
default--v0~2e1~2e0~5fhf--31fba451-22bb-5308-b5e8-6df402c6de09
task_revision_id
1
config / split
default / v0.1.0_hf

Official source

initial import