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BigCodeBench / BigCodeBench v0.1.0_hf 6aeac191-54ff-5a19-9eec-f4e29a5b7fa1

Problem

Answer published by the source. Consult the official source to check your work against its answer.

complete prompt

import pytz
import numpy as np
from dateutil.parser import parse
import math


MOON_PHASES_YEARS = np.array([1987, 1994, 2001, 2008, 2015, 2022])

def task_func(date_str, from_tz, to_tz):
    """
    Calculate the moon phase by the date and time taking into account the lunar phase cycle of 7 years. The 
    function uses a constant array `MOON_PHASES_YEARS` to determine the reference years for the moon phases.

    Parameters:
    date_str (str): The date string in "yyyy-mm-dd hh:mm:ss" format.
    from_tz (str): The timezone of the given date string.
    to_tz (str): The timezone to which the given date and time should be converted.

    Returns:
    float: The moon phase between 0 and 1. A value of 0 indicates a new moon and a value of 1 indicates a full moon.

    Requirements:
    - pytz
    - numpy
    - dateutil.parser
    - math

    Example:
    >>> task_func('1970-01-01 00:00:00', 'UTC', 'America/New_York')
    0.9749279121818237
    """

instruct prompt

Calculate the moon phase by the date and time taking into account the lunar phase cycle of 7 years. The function uses a constant array `MOON_PHASES_YEARS` to determine the reference years for the moon phases.
The function should output with:
    float: The moon phase between 0 and 1. A value of 0 indicates a new moon and a value of 1 indicates a full moon.
You should write self-contained code starting with:

Code

import pytz
import numpy as np
from dateutil.parser import parse
import math
MOON_PHASES_YEARS = np.array([1987, 1994, 2001, 2008, 2015, 2022])
def task_func(date_str, from_tz, to_tz):

code prompt

Code

import pytz
import numpy as np
from dateutil.parser import parse
import math
MOON_PHASES_YEARS = np.array([1987, 1994, 2001, 2008, 2015, 2022])
def task_func(date_str, from_tz, to_tz):

entry point

task_func

libs

  • dateutil
  • math
  • numpy
  • pytz

Discussion

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Source and history

task_id
6aeac191-54ff-5a19-9eec-f4e29a5b7fa1
task_key
default--v0~2e1~2e0~5fhf--6aeac191-54ff-5a19-9eec-f4e29a5b7fa1
task_revision_id
1
config / split
default / v0.1.0_hf

Official source

initial import