benchmarks.wiki / Public workspace
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╚═════╝ ╚═╝ ╚═════╝ ╚═════╝ ╚═════╝ ╚═════╝ ╚══════╝╚═════╝ ╚══════╝╚═╝ ╚═══╝ ╚═════╝╚═╝ ╚═╝$ open /benchmarks/bigcodebench/tasks/default--v0~2e1~2…▌ posts · files
BigCodeBench / BigCodeBench v0.1.0_hf a4f312d2-79af-53d6-a922-34c2441c30f6
Problem
Answer published by the source. Consult the official source to check your work against its answer.
complete prompt
import numpy as np
from scipy.stats import norm
def task_func(data: np.ndarray, threshold: float = 2.0) -> list:
"""
Determine the outlier indices in a 1D numpy array based on the Z score.
First a normal distribution is fitted to the data, the mean and standard
deviation is used to calculate the z scores of each datapoint.
If the absolute z score of a datapoint is larger than threshold it is
considered an outlier and its index is recorded.
If the standard deviation is 0, an empty list is returned as outliers.
Parameters:
data (numpy.ndarray): The 1D numpy array to check for outliers.
threshold (float): The outlier threshold. Defaults to 2.
Returns:
list: The indices of outliers in the data where Z score > threshold. Empty if standard deviation is 0
float: The mean of the fitted normal distribution.
float: The variance of the fitted normal distribution.
Requirements:
- numpy
- scipy.stats.norm
Example:
>>> data = np.array([1, 2, 3, 4, 5, 6, 100])
>>> task_func(data)
([6], 17.285714285714285, 1142.7755102040817)
>>> data = np.array([-10, 3, 5, 5, 5, 5, 5, 7, 20])
>>> outliers, mean, var = task_func(data, threshold=4)
>>> print(outliers)
[]
>>> print(mean)
5.0
>>> print(var)
50.888888888888886
"""
instruct prompt
Determine the outlier indices in a 1D numpy array based on the Z score. First a normal distribution is fitted to the data, the mean and standard deviation is used to calculate the z scores of each datapoint. If the absolute z score of a datapoint is larger than threshold it is considered an outlier and its index is recorded. If the standard deviation is 0, an empty list is returned as outliers. >>> data = np.array([-10, 3, 5, 5, 5, 5, 5, 7, 20]) >>> outliers, mean, var = task_func(data, threshold=4) >>> print(outliers) [] >>> print(mean) 5.0 >>> print(var) 50.888888888888886
The function should output with:
list: The indices of outliers in the data where Z score > threshold. Empty if standard deviation is 0
float: The mean of the fitted normal distribution.
float: The variance of the fitted normal distribution.
You should write self-contained code starting with:
Code
import numpy as np
from scipy.stats import norm
def task_func(data: np.ndarray, threshold: float = 2.0) -> list:
code prompt
Code
import numpy as np
from scipy.stats import norm
def task_func(data: np.ndarray, threshold: float = 2.0) -> list:
entry point
task_func
libs
- numpy
- scipy
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Source and history
- task_id
a4f312d2-79af-53d6-a922-34c2441c30f6- task_key
default--v0~2e1~2e0~5fhf--a4f312d2-79af-53d6-a922-34c2441c30f6- task_revision_id
- 1
- config / split
- default / v0.1.0_hf
initial import