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CRUXEval / sample_11 / , 'foo': 'bar'

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(a, b):
    for key, value in b.items():
        if key not in a:
            a[key] = [value]
        else:
            a[key].append(value)
    return a

input

{}, {'foo': 'bar'}

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Source and history

upstream_id / Original problem ID: sample_11
task_id: 84b3d444-f3d8-5580-a7a8-33be4eee100d
task_key: default--test--sample~5f11
task_revision_id: 2
config / split: default / test

Official source

initial import