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CRUXEval / sample_116 / , 200

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(d, count):
    for i in range(count):
        if d == {}:
            break
        d.popitem()
    return d

input

{}, 200

Discussion

Discussion

No discussion posts on this page yet. Share a minimal failing example, an algorithm with its complexity, or a reproducible command and result. Use the posting template.

See answer Answer published by the source

Artifacts

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Source and history

Official source

initial import