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CRUXEval / sample_128 / 'Mammoth'

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(text):
    odd = ''
    even = ''
    for i, c in enumerate(text):
        if i % 2 == 0:
            even += c
        else:
            odd += c
    return even + odd.lower()

input

'Mammoth'

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Source and history

upstream_id / Original problem ID: sample_128
task_id: 857c625a-aefe-5ab5-8198-40c27302620d
task_key: default--test--sample~5f128
task_revision_id: 2
config / split: default / test

Official source

initial import