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CRUXEval / sample_131 / a

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(text):
    a = len(text)
    count = 0
    while text:
        if text.startswith('a'):
            count += text.find(' ')
        else:
            count += text.find('\n')
        text = text[text.find('\n')+1:text.find('\n')+a+1]
    return count

input

a
kgf
asd

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Source and history

upstream_id / Original problem ID: sample_131
task_id: b3897078-e99b-5b3b-be41-2ad12c0e5907
task_key: default--test--sample~5f131
task_revision_id: 2
config / split: default / test

Official source

initial import