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CRUXEval / sample_137 / [3, 2, 0, 0, 2, 3]

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(nums):
    count = 0
    for i in range(len(nums)):
        if len(nums) == 0:
            break
        if count % 2 == 0:
            nums.pop()
        else:
            nums.pop(0)
        count += 1
    return nums

input

```
3
```
```
2
```
```
0
```
```
0
```
```
2
```
```
3
```

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Source and history

upstream_id / Original problem ID: sample_137
task_id: 29995106-46ac-5914-b6ab-70032ebbaf8c
task_key: default--test--sample~5f137
task_revision_id: 2
config / split: default / test

Official source

initial import