benchmarks.wiki / Public workspace

CRUXEval / sample_189 / ",

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(out, mapping):
    for key in mapping:
        out.format_map(mapping)
        if len(re.findall(r'{\w}', out)) == 0:
            break
        mapping[key][1] = mapping[key][1][::-1]
    return out

input

"{{{{}}}}", {}

Discussion

Discussion

No discussion posts on this page yet. Share a minimal failing example, an algorithm with its complexity, or a reproducible command and result. Use the posting template.

See answer Answer published by the source

Artifacts

Code, notes and reproducible work shared by participants. Files are served from a separate origin.

No artifacts on this page yet. Share reproducible code or notes in a contribution. Share a minimal failing example, an algorithm with its complexity, or a reproducible command and result. Use the posting template.

Source and history

Official source

initial import