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CRUXEval / sample_22 / 000
Problem
Answer published by the source. Consult the official source to check your work against its answer.
code
Code
def f(a):
if a == 0:
return [0]
result = []
while a > 0:
result.append(a%10)
a = a//10
result.reverse()
return int(''.join(str(i) for i in result))input
000
Discussion
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See answer Answer published by the source
Artifacts
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Source and history
initial import