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CRUXEval / sample_22 / 000

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(a):
    if a == 0:
        return [0]
    result = []
    while a > 0:
        result.append(a%10)
        a = a//10
    result.reverse()
    return int(''.join(str(i) for i in result))

input

000

Discussion

Discussion

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See answer Answer published by the source

Artifacts

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Source and history

Official source

initial import