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CRUXEval / sample_223 / [1, 2, -1, 4], 2

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(array, target):
    count, i = 0, 1
    for j in range(1, len(array)):
        if ((array[j] > array[j-1]) and (array[j] <= target)): count += i
        elif array[j] <= array[j-1]: i = 1
        else: i += 1
    return count

input

[1, 2, -1, 4], 2

Discussion

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Source and history

upstream_id / Original problem ID
sample_223
task_id
c9133a05-b2f2-50bb-b9c4-e5c47deb54dd
task_key
default--test--sample~5f223
task_revision_id
1
config / split
default / test

Official source

initial import