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CRUXEval / sample_224 / ['23'], 123

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(array, value):
    array.reverse()
    array.pop()
    odd = []
    while len(array) > 0:
        tmp = {}
        tmp[array.pop()] = value
        odd.append(tmp)
    result = {}
    while len(odd) > 0:
        result.update(odd.pop())
    return result

input

['23'], 123

Discussion

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Source and history

upstream_id / Original problem ID
sample_224
task_id
04f5a1dc-48dd-5f40-9c10-b8fe80548287
task_key
default--test--sample~5f224
task_revision_id
1
config / split
default / test

Official source

initial import