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CRUXEval / sample_229 / '9m':2, 'mA':1, '10K':2, 'Lk':2, 1

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(dic, value):
    result = []
    for e in dic:
        result.append(e[0])
        if e[1] == value:
            result.reverse()
        else:
            result.append(e[1])
    return result

input

{'9m':2, 'mA':1, '10K':2, 'Lk':2}, 1

Discussion

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Source and history

upstream_id / Original problem ID
sample_229
task_id
3c3508d2-2730-5238-a61b-9d5fec65298e
task_key
default--test--sample~5f229
task_revision_id
1
config / split
default / test

Official source

initial import