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CRUXEval / sample_232 / 'fssnvd', 'yes'

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(text, changes):
    result = ''
    count = 0
    changes = list(changes)
    for char in text:
        result += char if char in 'e' else changes[count % len(changes)]
        count += (1 if char not in 'e' else 0)
    return result

input

'fssnvd', 'yes'

Discussion

Discussion

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Source and history

upstream_id / Original problem ID
sample_232
task_id
d7ea6697-07ca-5544-9a6d-11b5298d0310
task_key
default--test--sample~5f232
task_revision_id
1
config / split
default / test

Official source

initial import