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CRUXEval / sample_233 / [1, 2, 3]

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(xs):
    for idx in reversed(range(-len(xs)-1, -1)):
        xs.insert(idx, xs.pop(0))
    return xs

input

  • 1
  • 2
  • 3

Discussion

Discussion

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See answer Answer published by the source

Artifacts

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Source and history

upstream_id / Original problem ID
sample_233
task_id
6b02e77e-b1de-5da4-9a5d-bb317de5a3de
task_key
default--test--sample~5f233
task_revision_id
1
config / split
default / test

Official source

initial import