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CRUXEval / sample_237 / 'uzlwaqiaj', 'u'

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(text, char):
    if char in text:
        suff, char, pref = text.partition(char)
        pref = suff[:-len(char)] + suff[len(char):] + char + pref
        return suff + char + pref
    return text

input

'uzlwaqiaj', 'u'

Discussion

Discussion

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See answer Answer published by the source

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Source and history

upstream_id / Original problem ID
sample_237
task_id
9df6fd9f-9086-5391-9da5-48078a4e68d6
task_key
default--test--sample~5f237
task_revision_id
1
config / split
default / test

Official source

initial import