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CRUXEval / sample_240 / 3.121

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(float_number):
    number = str(float_number)
    dot = number.find('.')
    if dot != -1:
        return number[:dot] + '.' + number[dot+1:].ljust(2, '0')
    return number + '.00'

input

3.121

Discussion

Discussion

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See answer Answer published by the source

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Source and history

Official source

initial import