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CRUXEval / sample_258 / thigh_o_two[:], 3, 3, 2

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

thigh_o_one = [1, 2, 7, 8, 9]
thigh_o_two = [1, 2, 7, 9]
def f(L, m, start, step):
    L.insert(start, m)
    for x in range(start-1, 0, -step):
        start -= 1
        L.insert(start, L.pop(L.index(m)-1))
    return L

input

thigh_o_two[:], 3, 3, 2

Discussion

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Source and history

upstream_id / Original problem ID
sample_258
task_id
bd23ea69-780e-560b-9bb9-d72b981ede48
task_key
default--test--sample~5f258
task_revision_id
1
config / split
default / test

Official source

initial import