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CRUXEval / sample_265 / 1: 2, 2: 4, 3: 3, 3

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(d, k):
    new_d = {}
    for key, val in d.items():
        if key < k:
            new_d[key] = val
    return new_d

input

{1: 2, 2: 4, 3: 3}, 3

Discussion

Discussion

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See answer Answer published by the source

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Source and history

Official source

initial import