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CRUXEval / sample_303 / 'mJkLbn'

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(text):
    i = (len(text) + 1) // 2
    result = list(text)
    while i < len(text):
        t = result[i].lower()
        if t == result[i]:
            i += 1
        else:
            result[i] = t
        i += 2
    return ''.join(result)

input

'mJkLbn'

Discussion

Discussion

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Source and history

upstream_id / Original problem ID
sample_303
task_id
51021823-6d67-58e3-bb9c-5abe39d6a950
task_key
default--test--sample~5f303
task_revision_id
1
config / split
default / test

Official source

initial import