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CRUXEval / sample_305 / 'o horseto', 'r'

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(text, char):
    length = len(text)
    index = -1
    for i in range(length):
        if text[i] == char:
            index = i
    if index == -1:
        index = length // 2
    new_text = list(text)
    new_text.pop(index)
    return ''.join(new_text)

input

'o horseto', 'r'

Discussion

Discussion

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See answer Answer published by the source

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Source and history

upstream_id / Original problem ID
sample_305
task_id
42034ffc-a23e-5beb-9835-54af57989da7
task_key
default--test--sample~5f305
task_revision_id
1
config / split
default / test

Official source

initial import