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CRUXEval / sample_318 / '234rtccde', 'e'

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(value, char):
    total = 0
    for c in value:
        if c == char or c == char.lower():
            total += 1
    return total

input

'234rtccde', 'e'

Discussion

Discussion

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Source and history

upstream_id / Original problem ID
sample_318
task_id
1eaaf73b-db23-5e46-9d26-b4fee31ea3d9
task_key
default--test--sample~5f318
task_revision_id
1
config / split
default / test

Official source

initial import