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CRUXEval / sample_32 / 'volume', 'l'

Problem

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code

Code

def f(s, sep):
    reverse = ['*' + e for e in s.split(sep)]
    return ';'.join(reversed(reverse))

input

'volume', 'l'

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Source and history

upstream_id / Original problem ID: sample_32
task_id: 74590f65-f558-5e24-a5c2-075f6856f5db
task_key: default--test--sample~5f32
task_revision_id: 2
config / split: default / test

Official source

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