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CRUXEval / sample_33 / [5, 2, 7, 2, 3, 5]

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(lists):
    dic = {}
    for n in lists:
        if n in dic:
            dic[n].append(lists.pop(lists.index(n)))
        else:
            dic[n] = lists[:lists.index(n) + 1]
    return str(dic).replace(' ', '')

input

  • 5
  • 2
  • 7
  • 2
  • 3
  • 5

Discussion

Discussion

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See answer Answer published by the source

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Source and history

Official source

initial import