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CRUXEval / sample_358 / 'btrburger', 'b'

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(text, value):
    indexes = []
    for i in range(len(text)):
        if text[i] == value and (i == 0 or text[i-1] != value):
            indexes.append(i) 
    if len(indexes) % 2 == 1:
        return text
    return text[indexes[0]+1:indexes[-1]]

input

'btrburger', 'b'

Discussion

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Source and history

upstream_id / Original problem ID
sample_358
task_id
419c795f-32c7-598f-b1ba-e552bf9b6818
task_key
default--test--sample~5f358
task_revision_id
1
config / split
default / test

Official source

initial import