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CRUXEval / sample_371 / [11, 21, 0, 11]

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(nums):
    for odd in nums[:]:
        if odd % 2 != 0:
            nums.remove(odd)
    sum_ = 0
    for num in nums:
        sum_ += num
    return sum_

input

  • 11
  • 21
  • 0
  • 11

Discussion

Discussion

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Source and history

upstream_id / Original problem ID
sample_371
task_id
898b83ea-dd42-5a3a-93d5-d411d81e485e
task_key
default--test--sample~5f371
task_revision_id
1
config / split
default / test

Official source

initial import