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CRUXEval / sample_375 / 'sierizam', 'iz'

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(a, b):
    if b in a:
        return b.join(a.partition(a[a.index(b) + 1]))
    else:
        return a

input

'sierizam', 'iz'

Discussion

Discussion

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See answer Answer published by the source

Artifacts

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Source and history

upstream_id / Original problem ID
sample_375
task_id
38bc03bd-7401-548a-a245-dc97fdd6d91c
task_key
default--test--sample~5f375
task_revision_id
1
config / split
default / test

Official source

initial import