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CRUXEval / sample_405 / [6, 3, 4, 1, 2, 3, 5]

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(xs):
    new_x = xs[0] - 1
    xs.pop(0)
    while(new_x <= xs[0]):
        xs.pop(0)
        new_x -= 1
    xs.insert(0, new_x)
    return xs

input

  • 6
  • 3
  • 4
  • 1
  • 2
  • 3
  • 5

Discussion

Discussion

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See answer Answer published by the source

Artifacts

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Source and history

upstream_id / Original problem ID
sample_405
task_id
8e500d27-b4c4-5d98-b053-4581d3e7a46e
task_key
default--test--sample~5f405
task_revision_id
1
config / split
default / test

Official source

initial import