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CRUXEval / sample_418 / qqqqq", "qqq"

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(s, p):
    arr = s.partition(p)
    part_one, part_two, part_three = len(arr[0]), len(arr[1]), len(arr[2])
    if part_one >= 2 and part_two <= 2 and part_three >= 2:
        return (arr[0][::-1] + arr[1] + arr[2][::-1] + '#')
    return (arr[0] + arr[1] + arr[2])

input

"qqqqq", "qqq"

Discussion

Discussion

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Source and history

upstream_id / Original problem ID
sample_418
task_id
f7e180a0-d1d5-5ac3-a6de-01c6312ea788
task_key
default--test--sample~5f418
task_revision_id
1
config / split
default / test

Official source

initial import