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CRUXEval / sample_451 / 'pn', 'p'

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(text, char):
    text = list(text)
    for count, item in enumerate(text):
        if item == char:
            text.remove(item)
            return ''.join(text)
    return text

input

'pn', 'p'

Discussion

Discussion

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Source and history

upstream_id / Original problem ID
sample_451
task_id
b67583a9-8b13-584f-94cb-09721e3229cf
task_key
default--test--sample~5f451
task_revision_id
1
config / split
default / test

Official source

initial import