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CRUXEval / sample_481 / [1, 1], 2, 3

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(values, item1, item2):
    if values[-1] == item2:
        if values[0] not in values[1:]:
            values.append(values[0])
    elif values[-1] == item1:
        if values[0] == item2:
            values.append(values[0])
    return values

input

[1, 1], 2, 3

Discussion

Discussion

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See answer Answer published by the source

Artifacts

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Source and history

upstream_id / Original problem ID
sample_481
task_id
477f494e-35fc-5b39-882c-ac76cf412d3d
task_key
default--test--sample~5f481
task_revision_id
1
config / split
default / test

Official source

initial import