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CRUXEval / sample_486 / 1:1, 2:2, 3:3

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(dic):
    dic_op = dic.copy()
    for key, val in dic.items():
        dic_op[key] = val * val
    return dic_op

input

{1:1, 2:2, 3:3}

Discussion

Discussion

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Source and history

upstream_id / Original problem ID
sample_486
task_id
6cfff4a8-a2be-5842-9a56-91afabd7df8b
task_key
default--test--sample~5f486
task_revision_id
1
config / split
default / test

Official source

initial import