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CRUXEval / sample_506 / 1

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(n):
    p = ''
    if n%2 == 1:
        p+='sn'
    else:
        return n*n
    for x in range(1, n+1):
        if x%2 == 0:
            p+='to'
        else:
            p+='ts'
    return p

input

1

Discussion

Discussion

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Source and history

upstream_id / Original problem ID
sample_506
task_id
19dfe10c-5220-5f59-9e65-618414d33456
task_key
default--test--sample~5f506
task_revision_id
1
config / split
default / test

Official source

initial import