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CRUXEval / sample_529 / [1, 2, 3]

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(array):
    prev = array[0]
    newArray = array[:]
    for i in range(1, len(array)):
        if prev != array[i]:
            newArray[i] = array[i]
        else:
            del newArray[i]
        prev = array[i]
    return newArray

input

  • 1
  • 2
  • 3

Discussion

Discussion

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See answer Answer published by the source

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Source and history

upstream_id / Original problem ID
sample_529
task_id
e1aa4168-1ebd-5858-b3fd-9f230284fdf0
task_key
default--test--sample~5f529
task_revision_id
1
config / split
default / test

Official source

initial import