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CRUXEval / sample_533 / 'a',

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(query, base):
    net_sum = 0
    for (key, val) in base.items():
        if key[0] == query and len(key) == 3:
            net_sum -= val
        elif key[-1] == query and len(key) == 3:
            net_sum += val
    return net_sum

input

'a', {}

Discussion

Discussion

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Source and history

upstream_id / Original problem ID
sample_533
task_id
366c5c1e-e13e-5d4c-875b-1d764c00c7cb
task_key
default--test--sample~5f533
task_revision_id
1
config / split
default / test

Official source

initial import