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CRUXEval / sample_572 / 1: 9, 2: 10, 3: 1, 1

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(data, num):
    new_dict = {}
    temp = list(data.items())
    for i in range(len(temp) - 1, num - 1, -1):
        new_dict[temp[i]] = None
    return temp[num:] + list(new_dict.items())

input

{1: 9, 2: 10, 3: 1}, 1

Discussion

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Source and history

upstream_id / Original problem ID
sample_572
task_id
adf13544-f7b9-55c7-a3a2-39c0991d96ed
task_key
default--test--sample~5f572
task_revision_id
1
config / split
default / test

Official source

initial import