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CRUXEval / sample_616 / '

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(body):
    ls = list(body)
    dist = 0
    for i in range(0, len(ls) - 1):
        if ls[i - 2 if i - 2 >= 0 else 0] == '\t':
            dist += (1 + ls[i - 1].count('\t')) * 3
        ls[i] = '[' + ls[i] + ']'
    return ''.join(ls).expandtabs(4 + dist)

input

'\n\ny\n'

Discussion

Discussion

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Source and history

upstream_id / Original problem ID
sample_616
task_id
bd4503bd-0729-5344-ad83-c5529a81ca63
task_key
default--test--sample~5f616
task_revision_id
1
config / split
default / test

Official source

initial import