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CRUXEval / sample_645 / [1, 1, 1, 2], 3

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(nums, target):
    if nums.count(0):
        return 0
    elif nums.count(target) < 3:
        return 1
    else:
        return nums.index(target)

input

[1, 1, 1, 2], 3

Discussion

Discussion

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Source and history

upstream_id / Original problem ID
sample_645
task_id
ed71467b-ce74-5cac-b565-8d1ec7be9db5
task_key
default--test--sample~5f645
task_revision_id
1
config / split
default / test

Official source

initial import