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CRUXEval / sample_678 / HI"

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(text):
    freq = dict()
    for c in text.lower():
        if c in freq:
            freq[c] += 1
        else:
            freq[c] = 1
    return freq

input

HI

Discussion

Discussion

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Artifacts

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Source and history

upstream_id / Original problem ID
sample_678
task_id
17b8ac55-d1d9-512a-8a17-059f1ef48385
task_key
default--test--sample~5f678
task_revision_id
1
config / split
default / test

Official source

initial import