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CRUXEval / sample_690 / '800'

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(n):
    if str(n).find('.') != -1:
        return str(int(n)+2.5)
    return str(n)

input

'800'

Discussion

Discussion

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Artifacts

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Source and history

upstream_id / Original problem ID
sample_690
task_id
3936ed21-0b26-53bb-b02a-22c12b7a0fcd
task_key
default--test--sample~5f690
task_revision_id
1
config / split
default / test

Official source

initial import