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CRUXEval / sample_695 / Problem discussion

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(d):
    result = {}
    for ki, li in d.items():
        result.update({ki: []})
        for kj, dj in enumerate(li):
            result[ki].append({})
            for kk, l in dj.items():
                result[ki][kj][kk] = l.copy()
    return result

input

{}

Discussion

Discussion

No discussion posts on this page yet. Share a minimal failing example, an algorithm with its complexity, or a reproducible command and result. Use the posting template.

See answer Answer published by the source

Artifacts

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Source and history

upstream_id / Original problem ID
sample_695
task_id
ffb1c62a-b276-5832-bf09-714aa2c909b2
task_key
default--test--sample~5f695
task_revision_id
1
config / split
default / test

Official source

initial import