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CRUXEval / sample_705 / ['Sydney', 'Hong Kong', 'Melbourne', 'Sao Paolo', 'Istanbul', 'Boston'],…

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(cities, name):
    if not name:
        return cities
    if name and name != 'cities':
        return []
    return [name + city for city in cities]

input

['Sydney', 'Hong Kong', 'Melbourne', 'Sao Paolo', 'Istanbul', 'Boston'], 'Somewhere '

Discussion

Discussion

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See answer Answer published by the source

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Source and history

Official source

initial import