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CRUXEval / sample_707 / 'undbs l', 1

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(text, position):
    length = len(text)
    index = position % (length + 1)
    if position < 0 or index < 0:
        index = -1
    new_text = list(text)
    new_text.pop(index)
    return ''.join(new_text)

input

'undbs l', 1

Discussion

Discussion

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Source and history

upstream_id / Original problem ID
sample_707
task_id
28f9391e-47fe-5fe6-9e5f-22c3b936606e
task_key
default--test--sample~5f707
task_revision_id
1
config / split
default / test

Official source

initial import